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parallel: Remove run_parallel.
This was a broken abstraction that returned to its caller within multiple forked processes on exceptions, and encouraged ignoring the error code (as all of its callers did). Signed-off-by: Anders Kaseorg <anders@zulipchat.com>
This commit is contained in:
committed by
Tim Abbott
parent
0f16df2f13
commit
a659542d84
@@ -1,74 +0,0 @@
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import errno
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import os
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import pty
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import sys
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from typing import Callable, Dict, Iterable, Iterator, Tuple, TypeVar
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JobData = TypeVar('JobData')
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def run_parallel(job: Callable[[JobData], int],
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data: Iterable[JobData],
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threads: int=6) -> Iterator[Tuple[int, JobData]]:
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pids: Dict[int, JobData] = {}
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def wait_for_one() -> Tuple[int, JobData]:
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while True:
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try:
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(pid, status) = os.wait()
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return status, pids.pop(pid)
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except KeyError:
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pass
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for item in data:
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pid = os.fork()
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if pid == 0:
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sys.stdin.close()
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try:
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os.close(pty.STDIN_FILENO)
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except OSError as e:
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if e.errno != errno.EBADF:
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raise
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sys.stdin = open("/dev/null")
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os._exit(job(item))
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pids[pid] = item
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threads = threads - 1
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if threads == 0:
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(status, item) = wait_for_one()
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threads += 1
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yield (status, item)
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if status != 0:
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# Stop if any error occurred
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break
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while True:
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try:
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(status, item) = wait_for_one()
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yield (status, item)
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except OSError as e:
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if e.errno == errno.ECHILD:
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break
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else:
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raise
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if __name__ == "__main__":
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# run some unit tests
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import time
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jobs = [10, 19, 18, 6, 14, 12, 8, 2, 1, 13, 3, 17, 9, 11, 5, 16, 7, 15, 4]
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expected_output = [6, 10, 12, 2, 1, 14, 8, 3, 18, 19, 5, 9, 13, 11, 4, 7, 17, 16, 15]
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def wait_and_print(x: int) -> int:
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time.sleep(x * 0.1)
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return 0
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output = []
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for (status, job) in run_parallel(wait_and_print, jobs):
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output.append(job)
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if output == expected_output:
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print("Successfully passed test!")
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else:
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print("Failed test!")
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print(jobs)
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print(expected_output)
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print(output)
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