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gather_subscriptions: Use the colors from the Subscription table.
(imported from commit c23829ad4141a97c61e21b970e5031eae20e24b4)
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@@ -726,41 +726,25 @@ def do_finish_tutorial(user_profile):
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do_add_subscription(user_profile, stream)
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def gather_subscriptions(user_profile):
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# This is a little awkward because the StreamColor table has foreign keys
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# to Subscription, but not vice versa, and not all Subscriptions have a
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# StreamColor.
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#
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# We could do this with a single OUTER JOIN query but Django's ORM does
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# not provide a simple way to specify one.
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# For now, don't display the subscription for your ability to receive personals.
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subs = Subscription.objects.filter(
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# For now, don't display subscriptions for private messages.
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subs = Subscription.objects.select_related().filter(
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user_profile = user_profile,
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active = True,
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recipient__type = Recipient.STREAM)
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with_color = StreamColor.objects.filter(subscription__in = subs).select_related()
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no_color = subs.exclude(id__in = with_color.values('subscription_id')).select_related()
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stream_ids = [sc.subscription.recipient.type_id for sc in with_color] + \
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[sub.recipient.type_id for sub in no_color]
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stream_ids = [sub.recipient.type_id for sub in subs]
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stream_hash = {}
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for stream in Stream.objects.filter(id__in=stream_ids):
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stream_hash[stream.id] = (stream.name, stream.invite_only)
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result = []
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for sc in with_color:
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(stream_name, invite_only) = stream_hash[sc.subscription.recipient.type_id]
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result.append({'name': stream_name,
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'in_home_view': sc.subscription.in_home_view,
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'invite_only': invite_only,
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'color': sc.color})
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for sub in no_color:
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for sub in subs:
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(stream_name, invite_only) = stream_hash[sub.recipient.type_id]
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result.append({'name': stream_name,
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'in_home_view': sub.in_home_view,
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'invite_only': invite_only,
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'color': StreamColor.DEFAULT_STREAM_COLOR})
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'color': sub.color})
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return sorted(result)
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